This is where the arithmetic gets most interesting, because the numbers split cleanly into separate problems that behave very differently, and Tesla's own figures are what separate them.
08
Ten thousand horsepower at a hundred million volts.
"I propose to distribute ten thousand horse-power under a tension of one hundred million volts… a transmitter will emit a wave complex of total maximum activity of ten million horse-power."
Electrical World and Engineer, 5 March 1904
FormulasP = hp × 745.7 W
I = P ÷ V
Z = V ÷ I
Inputs
- 10,000 hp = 7.457 MW, about 2,500 kettles boiling at once
- 10,000,000 hp = 7.457 GW, about seven large power station units
- V = 100,000,000 volts
- impedance of free space = 377 ohm
74.6 mAthe current his own two figures demand, less than a small torch draws
1.34 GΩthe source impedance that pairing describes
3.6 milliontimes the 377 ohm impedance of free space
140.6 Awhat the same power through 377 ohm would draw instead, at 53 kV
The pairing closes exactly on 75 milliamps. That number is the clearest single signature in the whole set of which regime he was designing in: an impedance six and a half orders of magnitude above free space describes a high-voltage, low-current displacement scheme, not a travelling-wave one. It is not a small detail of the design. It is the design, stated in one ratio, and it is his own arithmetic that states it.
09
Where the near field ends.
Lamps "lighted to full candle-power by currents induced in a local loop… at a distance of one hundred feet from the primary circuit."
Century Illustrated Magazine, June 1900
Close to a transmitter, energy sits in the surrounding field and comes back; far away, it leaves and does not. The boundary between the two is fixed by wavelength alone, at one wavelength divided by two π.
Formulad = λ ÷ 2π
Inputs
- frequencies from 6 Hz to 2.388 GHz
- the 1899 demonstration at 100 feet = 30.5 m
- the 2007 MIT demonstration at 2 m, 9.90 MHz
λ/181how far out the 1899 lamps sat, in wavelengths, at 100 feet and 54.24 kHz
λ/15how far out the 2007 MIT pair sat, at 2 m and 9.90 MHz
12 timeshow much deeper inside the near field the 1899 demonstration was
7,952 kmthe near-field radius at six per second, against an Earth radius of 6,371 km
Two things fall straight out of that table. The 1899 lamps and the 2007 laboratory result are the same regime measured at different scales, and the 1899 one is further inside it. And at six per second the near-field radius exceeds the radius of the Earth, so choosing that frequency puts the whole planet in the zone where energy is stored in the field rather than launched into it. Whatever else the six per second is, it is a choice that keeps everything inside the reactive zone, which is where the lamp demonstration was already working.
10
What radiating outward costs.
Take the 1904 target and let it spread in all directions. Power thins as the surface of a growing sphere, and what a receiver collects is that thinning multiplied by its own catching area.
FormulasS = P ÷ (4 π d²)
Pₕ = Pₜ Gₜ Gₕ (λ ÷ 4πd)²
Aₑ = G λ² ÷ 4π
Inputs
- P = 7.457 MW, his 10,000 horsepower
- f = 54.24 kHz, λ = 5.53 km
- gain 1.5 at each end, a plain resonant element
3.65 km²the catching area of one resonant element at 54.24 kHz, about 160 footy ovals
42,130 km²collector area to gather 1 kW at 5,000 km, about three fifths of Tasmania
205 kmthe side of that collector if it were square
57 millionthe factor by which received power falls short of the 1904 delivery target
Radiated outward in all directions, the 1904 power arrives across the Atlantic as 0.13 watts into a resonant element. That is a strong signal and it is a different thing from a power delivery, and the reason it is a strong signal is the low frequency: catching area grows with the square of the wavelength, so one element at 54 kilohertz effectively catches over 3.65 square kilometres. Low frequency buys enormous catching area per element. It is exactly why long-wave telegraphy worked across oceans, and the same arithmetic is what puts power delivery in a different class of problem.
11
Through the ground, and what the long-wave stations measure.
Claim 1: transmitting electrical energy "by conduction, through the earth and the air strata".
1923 testimony on the Wardenclyffe well: "to have a grip on the earth so the whole of this globe can quiver".
United States patent 645,576, filed 2 September 1897 · foreclosure testimony, 1923
Skin depth is the distance an alternating current sinks into a conductor before it drops to about a third of its surface value. It is set by the medium and the frequency, and not by how hard the transmitter is driven.
Formulasδ = √(2 ÷ (ω μ σ))
attenuation = 8.686 ÷ δ dB/m
Inputs, standard propagation values
- sea water 5 S/m, wet ground 0.01
- average ground 0.005, dry ground 0.001
- very dry rock 0.0003
Every ten decibels is another factor of ten, so 853,000 decibels is 85,300 factors of ten. That single column is the number that sends every practical system to a guided mode along the surface rather than bulk conduction through the crust.
The Wardenclyffe well is the other half of it, and here the arithmetic supports the engineering directly. Spreading resistance is the resistance an electrode meets as current fans out into the ground around it.
FormulaR = 1 ÷ (2 π σ a)
Inputs
- σ = 0.005 S/m, average ground
- a 120 foot shaft with sixteen iron pipes driven 300 feet deeper
31.8 Ωa one metre electrode
0.87 Ωthe 120 foot shaft taken on its own
0.32 Ωshaft plus pipes as a 100 metre effective hemisphere
90%of that resistance is spent within one kilometre of the electrode
The deep well is the right piece of engineering for the mechanism he described, and the arithmetic says why: growing the electrode from one metre to a hundred cuts the spreading resistance a hundredfold. It also says where the loss lives. Ninety per cent of it is within a kilometre of each end, and the path between two distant electrodes contributes almost nothing, which is why earth-return telegraphy worked across continents. The grip on the earth is real. What it grips is a resistive path whose whole cost is at the ends.
Then set his own quarter-wave rule against the largest station of this kind ever built. Project ELF, at Clam Lake in Wisconsin and Republic in Michigan, ran at 76 hertz on about 135 kilometres of ground-dipole line from 1989 until it was dismantled in September 2004.
Wardenclyffe's total vertical structure, 187 feet of tower plus a 120 foot shaft plus 300 feet of driven pipe, comes to 185 metres. That lands at 13.39 per cent of the electrical length the quarter-wave rule asks for at 54 kilohertz. Project ELF landed at 13.69 per cent. The two convergences are within a third of a per cent of each other, which makes Project ELF's measured performance the most directly informative number available for the launching problem: 8 watts radiated from 2.6 megawatts of input, a launch efficiency of three parts per million.
Radiation resistance goes as the square of that fraction, so the scaling is computable. Building the full 986 kilometres would raise the radiated power by a factor of 53, from 8 watts to about 427 watts, still 0.016 per cent efficient. Tesla's own rule and the measurement agree about where the difficulty sits, and they agree in advance of each other by ninety years. Loading coils supply the missing electrical length for tuning; they do not supply the radiating length. The two roles separate cleanly in the arithmetic.
The guided path itself is the cheap part, and this is the piece most easily lost. Measured attenuation in the Earth-ionosphere waveguide at these frequencies is 0.5 to 1 decibel per thousand kilometres, so 1.5 to 3 decibels across 3,000 kilometres, against roughly 9,000 decibels for bulk diffusion through the crust at the same frequency. Split the scheme into propagation and launch and they behave nothing alike.
4.19 MWwhat 7.457 MW launched into the guided mode leaves at 5,000 km
13.26 MWwhat would have to be radiated to deliver the full 7.457 MW there
4,310 GWthe input at Project ELF's measured launch efficiency, about 1.4 billion kettles
26.5 MWthe input at 50 per cent launch efficiency, which is one small power station
Propagation across a hemisphere costs ten to twenty decibels, which is affordable for power. Launch is where the entire budget goes, and the measured figure is three parts per million. Launch efficiency is the single quantity the whole scheme turns on, it is a structure-length problem, and the scaling law for it is the one written in his own patent from 1900.